11 April 2012
1. IP : 130.223.24.2/23
a. Berapa Network Addressnya?
b. Berapa broadcast Addressnya
c. Ada di blok subnet keberapa IP di atas?
d. IP ke berapa dalam blok subnet tersebut?
2. IP : 192.168.15.135/25
a. Berapa Network Addressnya?
b. Berapa broadcast Addressnya
c. Ada di blok subnet keberapa IP di atas?
d. IP ke berapa dalam blok subnet tersebut?
Jawab:
1. a. 10000010.11011111.00011000.00000010
11111111.11111111.11111110.00000000
========================================= AND
10000010.11011111.00011000.00000000
130 223 24 0
b. 10000010.11011111.00011000.00000010
11111111.11111111.11111110.00000000
=================================
teap............................................|jadi binar 1 semua
10000010.11011111.00011001.11111111
130 . 223 . 25 . 255
c. jumlah blok subnet 128 ke 13
d. 2
2.a. 11000000.10101000.00001111.10000111
11111111.11111111.11111111.10000000
================================== AND
11000000.10101000.00001111.100000000
192 . 168 . 15 . 128
b. 11000000.10101000.00001111.11111111
192 . 168 . 15 . 255
c. 3
d. 7
SOAL
1. Host address : 200.200.200.200/27
Pertanyaannya:
Ad di subnetwork ke berapa host ke berapa IP di atas?
2. Given the host address of 130.130.150.150/28
Find: a. Subnetwork
b. Broadcast Address
c. Subnet and host number to which the host belong!
Jawab
1. 11001000.11001000.11001000.11001000
11111111.11111111.11111111.11100000
========================================== And
11001000.11001000.11001000.11000000
200 . 200 . 200 . 192
jumlah subnet=2pngkat3=8
blok subnet 256-224=32
0,32,64,96,128,160,192 ke 7 dan ke 200-192= 8
2. 10000010.10000010.10010110.10010110
11111111.11111111.11111111.11110000
================================== AND
100000010.1000010.10010110.10010000
a. 130 . 130 . 150 . 144
b. 130.130.150.159
c. subnet dan host ke:
10000010.10000010.10010110.1001|0110
11111111.11111111.11111111.1111|0000
Subnet ke | host ke
subnet ke 2409+1=2410 host ke 6